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One Button On-Off circuit using 4017 IC.


Description of IC 4017B:
The 4017B is a monolithic IC fabricated in Metal Oxide Semiconductor technology available in DIP and SOP packages (I am using DIP package).
This is 5-stage Johnson counter having 10 decoded outputs (Q0 – Q9).
There are three inputs, one CLOCK, one RESET, and one ENABLE (or Inhibit).
To put this IC in working mode ENABLE must be kept low.
When high pulse is applied to CLOCK pin then IC counts this transition and shifts its output from Q0 to Q9.
To start counting from Q0, RESET pin must be kept low. (if you want to use all outputs, Q0 to Q9, then RESET pin will be always low. But in our circuit we will not use it in this way.

Circuit: 


This is very simple circuit, it uses only few components
4017 IC -               1 No.
1K Res -                                1 No.
470K Res-            1 No.
100nf Cap            1 No.
5mm Red LED-    1 No.
Tact Switch-        1 No.
Breadboard-      1 No.
9 V Battery-         1 No.
Few Jumper wire pieces, Tools, cutter etc.

We will work on only with 7 pins of this IC.
Pin No. 2, 4, 8, 13, 14, 15, 16.
Pin 2 is Output 1 from where we will take output status by connecting an LED via Resistor 1 K.
Pin 4 is Output 2, it will connect to pin no. 15 (RESET) to use this IC in our circuit.
Pin 8 is connected to –ve supply.
Pin 13 is connected to –ve supply.
Pin 14 is connected to –ve supply through 470K resistor (Pulled low).
Tact switch is connected between pin14 and pin 16.
100nf capacitor is connected between pin14 and pin16 (Cap is to stop de-bouncing of switch).
Pin 16 is connected to +ve supply.


Result of circuit:
Initially LED is off when button is pressed once LED becomes ON and, if again switch is pressed LED is OFF. On each press it toggles its state.




You can watch this circuit's assembly and working by going to given below address
For English Click here   



For Hindi Click here


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